Question

The molar conducatance of `Ba^(2+)` and `Cl^(-)` are `127` and `76 ohm^(-1) cm^(-1) mol^(-1)` respectively at infinite dilution. The equivalent conductance of `BaCl_(2)` at infinte dilution will be
A. `330 Omega^(-1) cm^(2)`
B. `203 Omega^(-1) cm^(2)`
C. `139.5 Omega^(-1) cm^(2)`
D. `51 Omega^(-1) cm^(2)`

Answer 1

Correct Answer - C
`Lambda_(m)^(oo)` for `BaCl_(2)=Lambda_(m)^(oo) Ba^(2+)+2Lambda_(m)^(oo)Cl^(-)`
`:. Lambda_(eq)^(oo)` for `BaCl_(2)=1/2 Lambda_(m)^(oo)Ba^(2+)+Lambda_(m)^(oo)Cl^(-)`
`=1/2 xx127+76=139.5 Omega^(-1) cm^(2)`