Correct Answer - A
`underset(sp^(3))overset(III)(CH_(3))-underset(sp^(3))overset(II)(CH_(2))-underset(sp)(C)-=underset(sp)overset(I)(CH)`
Electronegativity `prop` s-character
IN sp-hybrid orbitals, s-character = 50% and in `sp^(3)`-hybrid orbitals, s-character = 33.3% THus, i is the most electronegative.