A substance was known by its mode of synthesis to contain `10` atoms of carbon per molecule along with unknown number of atoms of chlorine, hydrogen and oxygen. Analysis showed 60.5% carbon 5.5% hydrogen, 16.10% oxygen and 17.9% chlorine. The molecular formula of compound is
A. `C_(10)H_(8)Cl_(2)`
B. `C_(10)H_(11)O_(2)Cl`
C. `C_(10)H_(10)Ocl`
D. `C_(10)H_(12)O_(2)Cl`