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`Zn+conc.HNO_(3) rarr Zn(NO_(3))_(2)+X+H_(2)O`
`Zn+dil.HNO_(3) rarr Zn(NO_(3))_(2)+Y+H_(2)O`
Compounds X and Y are respectively:
A. `N_(2)O,NO`
B. `N_(2),N_(2)O`
C. `NO_(2),NO`
D. `NO_(2),N_(2)O`

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Correct Answer - D
`NH_(4)OH.HCl+NaNO_(2)`
`underset(("Basic Oxide"))(rarrN_(2)O overset(Cu)(rarr)underset((B))(CuO))underset(underset(("Colourless, dia magnetic"))((x)))(+N_(2))`
`2Al+N_(2)rarr2AlN" "Zn+NaOHrarr(H_(2))`
The evolved `H_(2)` reduces `NaNO_(2)` to form `NH_(3)` gas

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