Question

When the current changes from `+2A` to `-2A` in `0.05s`, and emf of `8B` is induced in a coil. The coefficient of self-induction of the coil is
A. 0.1H
B. 0.2H
C. 0.4H
D. 0.8H

Answer 1

Correct Answer - A
`e = L (Deltal)/(Deltat)`
`therefore" "L= (e)/((Deltal)/(Deltat))=(8)/((4)/(0.05))= ( 8 xx 0.05)/(4)= 0.1 H`