Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
138 views
in Physics by (83.3k points)
closed by
the intensity of the magnetic induction field at the centre of a single turn circular coil of radius 5 cm carrying current of 0.9 A is
A. `36pixx10^(-7)T`
B. `9pixx10^(-7) T`
C. `36pixx10^(-6)T`
D. `9pixx10^(-6) T`

1 Answer

0 votes
by (78.7k points)
selected by
 
Best answer
Correct Answer - a
The intensity of magnetic induction filled
`B=(mu_(0)i)/(2r) =(4pixx10^(-7)xx0.9)/(2xx5xx10^(-2))`
`B=36 pi xx10^(-7) T`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...