Question

A glavanometer of `50 Omega` resistance has 25 divisions. A current of `4xx10^(-4)` A gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of `25 V`, it should be connected with a resistance of
A. `2500 Omega` as a shunt
B. `2950 Omega` as a shunt
C. `2550 Omega` in series
D. `2450 Omega ` in series

Answer 1

Correct Answer - d
Here, `I_(g)=25xx4xx10^(-4) A =10^(-2)A`
Convert the galvanometer into a voltmeter, we must join a series resistance of
`R=V/(I_(g))-G=25/(10^(-2)) -50 =2500 -50 =2450 Omega`