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In a circuit 5 percent of total current passes through a galvanometer. If resistance of the galvanometer is G then value of the shunt is
A. 19 G
B. `G/19`
C. 20 G
D. `G/20`

1 Answer

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Best answer
Correct Answer - b
Shunt of an ammeter,
`S=(I_(g)xxG)/(I-I_(g))=(5xxG)/(100-5)=G/19`

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