Correct Answer - A
Osmotic pressure`, pi = CRT`
Where, C= concentration of solution.
Given `w = 34.3g,V = 1L , M = 342 g mol^(-1)`.
`T = 20^(@)C, = 20 + 273 = 293^(@)K`.
`:. Pi = (W)/(MV)RT = (34.2)/(342 g mol^(-1)) xx (0.082L atm K^(-1) "mol"^(-1) xx 293 K)/(1L)`
`= 2.40` atm