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Write Arrhenius equation. Derive on expression for temperature variations.

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Arrhenius equation :
`K=A.e^(-Ea//RT)`
`"or ln K"=lnA-(E_(a))/(RT)`
`"pr "log_(10)K=log_(10)K-(E_(a))/(2.303RT)`
Arrhenius equation at two different temperatures
`log_(10)K_(1)=log_(10)A-(E_(a))/(2.303RT_(1))" ...(1)"`
`log_(10)K_(2)=log_(10)A-(E_(a))/(2.303RT_(1))" ...(2)"`
Equation (2) - (1)
`log_(10)K_(2)-log_(10)K_(1)=-(E_(a))/(2.303RT_(2))+(E_(a))/(2.303RT_(1))`
`therefore" "log_(10).(E_(a))/(2.303R)[(1)/(T)-(1)/(T_(2))]`
`therefore" "log_(10).(K_(2))/(K_(1))=(E_(a))/(2.303R)[(T_(2)-T_(1))/(T_(1)T_(2))]`

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