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A system absorbs 640 J heat and does work of 260 J, the change in internal energy of the system will be :
A. `+380J`
B. `-380J`
C. `+900J`
D. `-900J`

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Best answer
Correct Answer - B
The system has been given internal energy of 640 J and the work system does on surroundings is 260 J.
Therefore, by first law of thermodynamics the internal energy of system increases by
`-q=DeltaU-W=(-640+260)=-360J`

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