Question

How many moles of acetic anhydride will be required to form glucose pentaacetate from 2 M of glucose ?
A. 2
B. 5
C. 10
D. `2*5`

Answer 1

Correct Answer - B
When ecetylated with acetic anhydride `(-O-overset(O)overset(||)(C)-CH_(3))`, glucose forms a pentaacetate. The reaction is as follows :

In the given reaction, 1 M of glucose is producing glucose pentaacetate i.e., it contains 5 OAC group. Hence, 5 moles of acetic anhydride will be required to form from glucose pentaacetate from 2 M of glucose.