Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
125 views
in Mathematics by (92.5k points)
closed by
If `lim_(x to 1)((e^(k)-1)sin kx)/(x^(2))=4`, then k is equal to
A. 2
B. `-2`
C. `pm2 `
D. `pm4`

1 Answer

0 votes
by (90.6k points)
selected by
 
Best answer
Correct Answer - C
`lim_(x to oo ) ""((e^(kx)-1) sin kx)/( x^(2))=4 `
`implies lim_(x to 0)[(e^(kx) sin kx)/( x^(2))-(sin kx)/(x^(2))]=4 `
`implies lim_(x to 0)""[( e^(kx) cos kx * k +ke^(kx) sin kx)/(2 x)-( k cos kx )/(2 x)]=4 `
`implies lim_(x to 0)[( k^(2)e^(kx) cos kx-k^(2)e^(kx) sin kx +k^(2)e^(kx) sin kx +k^(2)e^(kx) cos ks )/(2) +(k^(2) sin kx )/( 2)]=4 `
`implies (k^(2)-0+0+k^(2))/(2)+0 =4 `
`implies k^(2)=4 `
`implies k= pm2`

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...