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The oxidation number of C atom in ` CH _ 2 Cl _ 2 and CCl_ 4 ` are respectively
A. ` - 2 and 4 `
B. ` 0 and - 4 `
C. ` 0 and 4 `
D. ` 2 and 4 `

1 Answer

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Correct Answer - C
Let the oxidation number of C is x
` CH _ 2 Cl _ 2 `
` x + 2 ( + 1 ) + 2 ( -1 ) = 0 `
` x + 2 - 2 = 0 `
` x = 0 `
` C Cl _ 4 `
` x + 4 ( - 1 ) = 0`
` x - 4 = 0`
` x = 4 `

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