Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
92 views
in Trigonometry by (79.1k points)
closed by
`sqrt((1+sintheta)/(1-sintheta))+sqrt((1-sintheta)/(1+sintheta))` is equal to
A. `2costheta`
B. `2sintheta`
C. `2cottheta`
D. `2sectheta`

1 Answer

0 votes
by (88.8k points)
selected by
 
Best answer
Correct Answer - d
`sqrt((1+sintheta)/(1-sintheta))+sqrt((1-sintheta)/(1+sintheta))`
`=((sqrt(1+sintheta))^(2)+(sqrt(1-sintheta))^(2))/(sqrt( 1-sin^(2)theta))`
`=(1+sintheta=1-sintheta)/(cos theta)`
`=(2)/(cos theta)=2sectheta`
Aternate shortcut method
Put `theta=30^(@)`
`sqrt((1+sin30^(@))/(1-sin30^(@)))+sqrt((1-sin30^(@))/(1+sin30^(@)))`
`rArrsqrt((1+(1)/(2))/(1-(1)/(2)))+sqrt((1-(1)/(2))/(1+(1)/(2)))`
`rArrsqrt((3)/(1))+sqrt((1)/(3))` ltbr gt `rArr(4)/sqrt(3)`
Now check with options by puting `theta=30^(@)`
`2 sec30^(@)=(2xx2)/sqrt(3)=(4)/sqrt(3)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...