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in Trigonometry by (79.1k points)
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If `(sec^(2)70^(@)-cot^(2)20^(@))/(2(co s ec^(2)59^(@)-tan^(2)31^(@)))=(2)/(m)`, then m is equal to
A. 2
B. 3
C. 4
D. 1

1 Answer

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Best answer
Correct Answer - c
`(sec^(2)70^(@)-cot^(2)20^(@))/(2(co s ec^(2)59^(@)-tan^(2)(90^(@)-59^(@))))=(2)/(m)`
`(sec^(2)70^(@)-cot^(2)(90^(@)-70^(@)))/( 2(cose c^(2)59^(@)-tan^(2)(90^(@)-59^(@))))=(2)/(m)`
`(sec^(2)70^(@)-tan^(2)70^(@))/(2(co s ec^(2)59^(@)-tan^(2)(90-59^(@))))=(2)/(m)`
`=(1)/(2)=(2)/(m)[sec^(2)theta-tan^(2)70^(@) co s ec^(2)theta-cot^(2)theta =1]`
`m=2xx2=4`

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