Correct Answer - c
`(sec^(2)70^(@)-cot^(2)20^(@))/(2(co s ec^(2)59^(@)-tan^(2)(90^(@)-59^(@))))=(2)/(m)`
`(sec^(2)70^(@)-cot^(2)(90^(@)-70^(@)))/( 2(cose c^(2)59^(@)-tan^(2)(90^(@)-59^(@))))=(2)/(m)`
`(sec^(2)70^(@)-tan^(2)70^(@))/(2(co s ec^(2)59^(@)-tan^(2)(90-59^(@))))=(2)/(m)`
`=(1)/(2)=(2)/(m)[sec^(2)theta-tan^(2)70^(@) co s ec^(2)theta-cot^(2)theta =1]`
`m=2xx2=4`