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In `triangleABC, ltB=90^(@) and AB:BC=BC=2:1` Then value of (SinA+CotC)(है तो (SinA+CotC) का मान ज्ञात करे )
A. `3+sqrt5`
B. `(2+sqrt5)/(2sqrt5)`
C. `2sqrt5`
D. `3+sqrt5`

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Correct Answer - b
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`AC=sqrt(2^(2)+1^(4))=sqrt(5)`
`sinA+cotC`
`(BC)/(AC)+(BC)/(AB)`
`(1)/sqrt(5)+(1)/(2)rArr(2+sqrt(5))/(2sqrt(5))`

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