Find dy/dx, if x = t^2 + t + 1, y = sin(πt/2) + cos(πt/2) at t = 1

Question

Find dy/dx, if

x = t² + t + 1, y = \(sin(\frac{\pi t}{2}) + cos(\frac{\pi t}{2})\)

x = t² + t + 1, y = sin(πt/2) + cos(πt/2) at t = 1

Answer 1

x = t² + t + 1, y = sin(πt/2) + cos(πt/2)

Differentiating x and y w.r.t. t, we get