Correct Answer - A
According to question, Given,
`2angleA= 3angleB`
`(angleA)/(angleB)= 3/2` `(3angleB)=(6angleC)`
`(angleB)/(angleC)= 6/3 = 2/1`
To make anlge `angleB` same
`therefore angleA : angleB: angleC`
`3 : 2: 1`
As we know that
`angleA+angleB+angleC= 180^(@)`
`x=30^(@)`
`angleB =2x=60^(@)`
