Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
172 views
in Geometry by (88.8k points)
closed by
यदि तो त्रिभुजों के शीर्ष लम्बो का अनुपात `4:5` हे, उनके क्षेत्रफल का अनुपात `3:2` हे। उनके तदनुरूपी (सांगत) आधारों का अनुपात क्या होगा?
A. `5:8`
B. `15:8`
C. `8:5`
D. `8:15`

1 Answer

0 votes
by (79.1k points)
selected by
 
Best answer
Correct Answer - B
`("area of triangle1")/("area of triangle 2")=3/2`
`(1/2 xx B_(1) xx 4)/(1/2 xx B_(2)xx5)=3/2`
`B_(1)/B_(2)=3/2 xx 5/4=15/8`
`B_(1) : B_(2) = 15:8`

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...