Question

A `50 Hz AC` source of `20 V` is connected across `R ` and `C` as shown in figureure.

The voltage across `R` is `12 V`. The voltage across `C` is
A. 8 V
B. 16 V
C. 10 V
D. not possible to determine unless values of R and C are given

Answer 1

Correct Answer - B
`V_("source")=sqrt(V_(R)^(2)-V_(C)^(2))`
`:. V_(C)=sqrt(V_("Source")^(2)+V_(C)^(2))`
`" " sqrt((20)^(2)-(12)^(2))=16V`