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Write the isomers of the compound having formula `C_(4)H_(9)Br`.

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Double bond equivalent (DBE) for `C_(4)H_(9)Br`
`=(4(4-2)+9(1-2)+1(1-2))/(2)+1=0`
So none of the isomer has a ring or unsaturation, so the isomers are position of chain isomers
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