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Correct method to prepare `Me_(3)C-O-Me` in good yield is /are :

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Correct method to prepare `Me_(3)C-O-Me` in good yield is /are :
A. `Me_(3)C-Cl+MeONararr`
B. `Me_(2)C=CH_(2)underset((ii)SBH)overset((ii)Hg(O Ac)_(2)+MeOH)rarr`
C. `Me_(3)C-O Na+MeClrarr`
D. `Me_(2)C=CH_(2)underset(MeOH)overset(H^(o+))rarr`
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Correct Answer - b,c,d
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