Correct Answer - AB
Contribution made by the atoms (A)
Contribution on the corners `=8xx1//8=1`
Contribution on the faces `=6xx1//2=3`
`therefore` No. of atoms of A present = 1 + 3 = 4
Contribution made by the atoms (B)
Contribution on one edge = 1/4
Contribution on all the twelve edges `=12xx1//4=3`
Contribution on the body centre = 1
`therefore` No. of atoms of B present = 3 + 1 = 4
The formula of the compound : `A_(4)B_(4)` or AB.