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in Biology by (62.0k points)

Number of meiotic divisions required to produce 200/400 seeds of pea would be

(a) 200/400 

(b) 400/800 

(c) 300/600 

(d) 250/500

1 Answer

+1 vote
by (63.1k points)
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Best answer

Correct option (d) 250/500

Explanation

200 seeds of pea would be produced from 200 pollen. grains and 200 embryo sacs- 200 pollen grains will be formed by 50 microspore mother cells, while 200 embryo sacs will be formed by 200 megaspore mother cells. Similarly 400 seeds of pea would i.e produced from 400 pollen grains and 400 embryo sacs. 400 pollen grains will be formed by 100 Microspore Mother Cell (MMC) and 400 embryo sacs formed by 400 Megaspore Mother Cell (MMC). Thus, number of meiotic divisions required to produce 200/400 seeds would be 250/500.

 

by (10 points)
+1
It can't be solved from (n+n/4)? If, then plzz solve......... what should I put in place of n......... I'm solving but the answer coming  is not like option which this question have.
by (10 points)
+1
I'm not sure but it would solve like first put 200 in place of n and through formula we'll get 250 then next time put 400 in place of n and solve from that formula and we'll get 500. So, overall answer will come 250/500.
200+200/4=250
400+400/4=500
250/500  
this we called 'biomathematics'
Don't solve by putting overall value in place of n i.e 200/400 solve separately

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