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The equation `sin^-1x-cos^-1x=cos^-1(sqrt3/2)` has

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The equation `sin^-1x-cos^-1x=cos^-1(sqrt3/2)` has
A. No solution
B. Unique solution
C. Infinite solution
D. None of these
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1 Answer

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Correct Answer - B
`"sin"^(-1)x-"cos"^(-1) x="cos"^(-1)((sqrt(3))/(2))`
`rArr (pi)/(2) -"cos"^(-1)x-"cos"^(-1)x="cos"^(-1)((sqrt(3))/(2))`
`rArr (pi)/(2)-(pi)/(6) =2 "cos"^(-1) x`
`rArr"cos"^(-1) x=(pi)/(6)`
`rArrx=(sqrt(3))/(2)`
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