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Why is `CH_(2)=CH-COOH` a stronger acid than `CH_(3)CH_(2)COOH`?

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This can be explained on the basis of conjugation as well as electronegativity,
(i) In the `prop`, `beta` unsaturated acid, the carbanion is stabilised by resonance or conjugation effect. This is not possible in `CH_(3)CH_(2)COOh`.
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(ii) In the unsaturated acid, the carbon atom to which carboxyl group is attached is more electronegative `(sp^(2)` hybridised) as compared to the carbon atom `(sp^(3) hybridised)` in the other acid. Therefore, the release of proton `(H^(+))` from unsaturated acid is easier and it is therefore, a stronger acid.

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