Question

A graph plotted between log `t_(50%)` vs log concentration is a straight line. What conclusion can you draw from this graph?

A. n = 1 , `t_(1//2) = (1)/(Ka)`
B. n = 2 , `t_(1//2) = 1//a`
C. `n = 1 , t_(1//2) = (0.693)/(K)`
D. None of these

Answer 1

Correct Answer - C
`t_(1//2 ) alpha a^(1-n) `
Or `t_(1//2) = k a^(1-n)`
log `t_(1//2) = "log" k + ( 1-n) "log a"`
`therefore` slope = 1 - n
or 1 - n = 0
or n = 1