Question

Solve the equation `x^(log_(x)(x+3)^(2))=16`.

Answer 1

Correct Answer - `x epsilon phi`
`x^(log_(x)(x+3)^(2))=16`…….i
Equatioin is defined when
`xgt0, x!=1, x!=-3,`
Then `(x+3)^(2)=4^(2)` [ by property]
`impliesx+3=+-4`
`:.x=1` and `x=-7`
But `x!=1, x!=-7`
i.e. no solution ltbr `:.x epsilon phi`