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किसी कुण्डली का प्रतिरोध 3 ओम तथा प्रतिघात ओम है, उसकी प्रतिबाधा कितनी होगी ?

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किसी कुण्डली का प्रतिरोध 3 ओम तथा प्रतिघात ओम है, उसकी प्रतिबाधा कितनी होगी ?
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सूत्र- `Z=sqrt(R^(2)+X_(L)^(2))`
दिया है- R=3 ओम तथा `X_(L)=4` ओम
`:.Z=sqrt(3^(2)+4^(2))=sqrt(9+16)=5` ओम।
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