Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
122 views
in Algebra by (93.6k points)
closed by
Let `alpha, beta, gamma` be distinct real numbers. The points with position vectors `alpha hati + beta hatj +gamma hat k , beta hati + gamma hatj +alpha hat k , gamma hati +alpha hatj + beta hatk`
A. are collinera
B. form an equilateral triangle
C. form a scalene triangle
D. form a right angled triangle

1 Answer

0 votes
by (92.3k points)
selected by
 
Best answer
Let given point be A, B and C with positive vectors `alphahati+betahatj+gammahatk,betahati+gammahatj+alphahatk and gamma hati+alphahatj+betahatk`
As `alpha,beta and gamma` are distinct real numbers, therefore ABC form a triangle.
Clearly, `AB=OB-OA=(betahati+gammahatj+alphahatk)-(alphahati+betahatj+gammahatk)`
`=(beta-alpha)hati+(gamma-beta)hatj+(alpha-gamma)hatk`
image
Now, `|AB|=sqrt((beta-alpha)^(2)+(gamma-beta)^(2)+(alpha-gamma)^(2))`
Similarly, `BC=CA=sqrt((beta-alpha)^(2)+(gamma-beta)^(2)+(alpha-gamma)^(2))`
`thereforeDeltaABC` is an equilateral triangle.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...