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If D, E and F are respectively, the mid-points of AB, AC and BC in `DeltaABC`, then BE + AF is equal to
A. DC
B. `(1)/(2)BF`
C. `2BF`
D. `(3)/(2)BF`

1 Answer

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Best answer
Correct Answer - A
`BE+AF=OE-OB+OF-OA`
image
`=(OA+OC)/(2)-OB+(OB+OC)/(2)-OA`
`=OC-(OA+OB)/(2)=OC-OD=DC`

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