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सोडियम के स्पेक्ट्रमी उत्सर्जन रेखा के प्रकाश का तरंगदैघ्र्य 589 nm है | वह गतिज ऊर्जा ज्ञात कीजिय जिस पर एक इलेक्ट्रॉन तरंगदैघ्र्य समान होगा |

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दिया है --- `lamda = 589 nm = 589 xx 10^(-9)m`
`lamda = h/sqrt(2mk)`
या `lamda^2 = h^2/(2mk)`
या `k = h^2/ (2n lamda^2), ` ( जहां k गतिज ऊर्जा )
इलेक्ट्रॉन की गतिज ऊर्जा `= ((6*6 xx 10^(-34))^2)/(2xx9*1xx10^(-31)xx(589 xx 10^(-9))^2)`
` = 6*898 xx 10^(-25)J`
`=(6*95 xx10^(-25))/(1*6 xx 10^(-19))eV`
` = 4* 34 xx 10^(-6) eV`.

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