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एक इलेक्ट्रॉन और एक फोट्रोन प्रत्येक का तरंगदैघ्र्य `1*00 nm `है | इलेक्ट्रॉन की गतिज ऊर्जा ज्ञात कीजिय |

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दिया है = `lamda = 1 nm = 1 xx 10^(-9) m`
` h = 6*63 xx 10^(-34) "J-sec"`
इलेक्ट्रॉन की गतिज ऊर्जा `k = p^2/(2m)`
` = ((6*63xx10^(-25))^2)/(2xx9*1xx10^(-31)) =2*41 xx 10^(-19)J`
` = (2*42 xx 10^(-19))/(1*6 xx 10^(-19))=1*51 eV`

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