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`""_(82)^(205)"Pb"` के नाभिक की त्रिज्या `7.531xx10^(-15)` मीटर है | तो `""_(8)^(16)O` की नाभिक की त्रिज्या निकालिए |

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यदि नाभिक की त्रिज्या R हो, तो
`R=R_(0)A^(1//3)`
`:." "R_(1)" और "R_(2)` त्रिज्या के दो नाभिकों के लिए,
`R_(1)=R_(0)A_(1)^(1//3)" एवं "R_(2)=R_(0)A_(2)^(1//3)`
`:." "(R_(1))/(R_(2))=((A_(1))/(A_(2)))^(1//3)`
Pb के लिए `A_(1)=205" तथा "R_(1)=7.531xx10^(-15)` मीटर तथा O के लिए `A_(2)=16` एवं `R_(2)=?`
`:." "(R_(1))/(R_(2))=((205)/(16))^(1//3)`
या `" "R_(2)=R_(1)xx((16)/(205))^(1//3)`
`=7.531xx10^(-15)xx((16)/(205))^(1//3)`
या `" "R_(2)=7.531xx10^(-15)xx(0.078)^(1//3)`
या `" "R_(2)=7.531xx10^(-15)xx0.4273`
या `" "R_(2)=3.218xx10^(-15)` मीटर |

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