दिया हैं: `k_(1) = 4.5 xx 10^(3) s^(-1), k_(2) = 1.5 xx 10^(4) s^(-1)`,
`T_(1) = 10+27 = 283 K, T_(2)=?, E_(a) = 60 kJ mol^(-1)`
`log_(10) (k_(2)/k_(1)) = E_(a)/(2.303 R) [1/T_(1) - 1/T_(2)]`
`log_(10) (1.5 xx 10^(4))/(4.5 xx 10^(3)) = 60/(2.303 xx 8.314 xx 10^(-3)) [1/283 -1/T_(2)]`
`0.523 = 3133.627 (1/283 - 1/T_(2))`
`1/T_(2) = (1/283 - 0.523/3133.627)`
`=0.0035 - 0.000167 = 3.33 xx 10^(-3)`
`T_(2) = 1/(3.33 xx 10^(-3)) = 300.03K = 27.30^(@)` C