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If (a + b + c)(a – b + c) = a2 + b2 + c2 , show that a, b, c are in continued proportion.

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(a + b + c)(a – b + c) = a2 + b2 + c2 …[Given] 

∴ a(a – b + c) + b(a – b + c) + c(a – b + c) = a2 + b2 + c2 

∴ a2 – ab + ac + ab – b2 + be + ac – be + c2 = a2 + b2 + c2 

∴ a2 + 2ac – b2 + c2 = a2 + b2 + c2

∴ 2ac – b2 = b2 

∴ 2ac = 2b2 

∴ ac = b2 

∴ b2 = ac 

∴ a, b, c are in continued proportion.

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