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निम्न फलनों का समाकलन कीजिए - `x sin 2xcos 2x`

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Correct Answer - `-(xcos4x)/8=1/32sin4x`
`intx sin2xcos2xdx=1/2intx (2sin2xcos2x)dx=1/2intx sin4xdx`
`1/2[x intsin4xdx-int{d/(dx)(x) intsin4xdx}dx]`

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