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बेन्जोइक अम्ल का मेथेनॉल 250ml में `0.15m` विलयन बनाने के लिए आवश्यक मात्रा की गणना कीजिए .

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`V=250 ml, m =0.15m, C_(6)H_(5)COOH=122,` विलेय की मात्रा=?
`m=("विलेय का भार")/(" अणुभार")xx(1000)/(" विलयन का आयतन mL में")`
`0.15 =(W)/(122)xx (1000)/(250)`
`W=(0.15xx122xx250)/(1000)=4.575g`

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