Correct Answer - B
Given ` l = 5 + 10 sin omega t`
`I_(eff) = [(int_(0)^(T) I^(2)dt)/(int_(0)^(T) dt)]^(1//2) = [ (1)/(T) int_(0)^(T) ( 5 + 10 sin omegat)^(2)dt]^(1//2)`
` = [(1)/(T) int_(0)^(T) (25+ 100 sin omegat dt =0 and (1)/(T)int_(0)^(T) sin^(2) omegat dt =(1)/(2)`
So `I_("eff")=[25+1/2xx100]^(1//2) = 5sqrt(3)A`