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The nucleus of helium atom contains two protons that are separated by distance `3.0xx10^(-15)m`. The magnitude of the electrostatic force that each proton exerts on the other is
A. 20.6 N
B. 25.6 N
C. 15.6 N
D. 12.6 N

1 Answer

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Best answer
Correct Answer - B
Charge of proton is `q_(p)=1.6xx10^(-19)C`
Distance between the protons is, `r=3xx10^(-15)m`
The magnitude of electrostatic force between protons is
`F_(e)=(q_(p)q_(p))/(4piepsilon_(0)r^(2))=(9xx10^(9)xx1.6xx10^(-19)xx1.6xx10^(-19))/((3xx10^(-15))^(2))=25.6N`

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