Correct Answer - D
From diagram, force on `q_(1)(=q)` at A,
`vecF_(1)=vecF_(12)+vecF_(13)=Foverset(""^^)(r)_(1)`
where `F=q^(2)/(4piepsilon_(0)l^(2))and oversetwedge(r)_(1)`, is the unit vector along BC
Force on `q_(2)(=q)` at B, `vecF_(2)=vecF_(21)+vecF_(23)=Foversetwedge(r)_(2)`
(where `oversetwedge(r)_(2)` is the unit vector along AC)
Force on `q_(2)(=-q)` at C,
`vecF_(3)=vecF_(31)+vecF_(32)=(sqrt(F^(2)+F^(2)+2F Fcos60^(@)))oversetwedge(n)=sqrt3Foversetwedge(n)`
where `oversetwedge(n)` = unit vector along the direction bisecting `angleBCA`
`therefore" "vecF_(1)+vecF_(2)+vecF_(3)=0`