Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.1k views
in Physics by (90.7k points)
closed by
Consider a thin spherical shell of radius R consisting of uniform surface charge density `sigma`. The electric field at a point of distance x from its centre and outside the shell is
A. inversely proportional to `sigma`
B. directly proportional to `x^(2)`
C. directlr proportional to R
D. inversely proportional to `x^(2)`

1 Answer

0 votes
by (91.3k points)
selected by
 
Best answer
Correct Answer - D
For a thin uniformly charged spherical shell,
the field points outside the shell at a distance x from the centre is
`E=1/(4piepsilon_(0))Q/x^(2)`
If the radius of the sphere is R. `Q=sigma4piR^(2)`
`therefore" " E=1/(4piepsilon_(0))(sigma4piR^(2))/x^(2)=(sigmaR^(2))/(epsilon_(0)x^(2))`
This is inversely proportional to square of the distance from the centre. It is as if the whole charge is concentrated at the centre.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...