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The operating magnetic field for accelerating protons in a cyclotron oscillator having frequency of 12 MHz is `(q= 1.6 xx 10^(-19) C, m_(p) = 1.67 xx 10^(-27) kg and 1 MeV = 1.6 xx 10^(-13J))`
A. 0.69T
B. 0.79T
C. 0.59T
D. 0.49T

1 Answer

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Best answer
Correct Answer - B
`B=(2pi m_(p)upsilon)/(q)`
`=(2xx3.14xx1.67xx10^(-27)xx12xx10^(6))/(1.6xx10^(-19))=0.79T`

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