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A uniform conducting wire of length length 10a and resistance R is wound up into four turn as a current carrying coil in the shape of equilateral triangle of side a. If current I is flowing 4 through the coil then the magnetic moment of the coil is image
A. `(sqrt3)/(2)a^(2)I`
B. `(a^(2)I)/sqrt3`
C. `sqrt3a^(2)I`
D. `(2a^(2)I)/(sqrt3)`

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Best answer
Correct Answer - C
Magnetic moment M = NIA
`=4xxIxxa^(2)(sqrt3)/(4)=sqrt3a^(2)I`

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