The natural boron of atomic weight 10.81 is found to have two isotopes `.^10B` and `.^11B` .The ratio of abundance of isotopes o

Correct Answer - d
Let abundance of `B^10` be x%
`therefore` Abundance of `B^11` = (100-x)%
`therefore 10.81=((10 xx x)+11(100-x))/100`
or 1081=10x + 1100 - 11x or x=19
`therefore` Ratio of abundance =`19/(100-19)=19/81`

The natural boron of atomic weight 10.81 is found to have two isotopes `.^10B` and `.^11B` .The ratio of abundance of isotopes of natural boron should

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