A fission reaction is given by `._(92)^(236)U rarr ._(54)^(140)Xe + ._(54)^(140)Xe + ._(38)^(94)Sr + x +y`, where `x` and `y` are two particles. Considering `._(92)^(236)U` to be at rest, the kinetic energies of the products are denoted by `K_(xe),K_(Sr),K_(x)(2MeV)` and `K_(y)(2Me V)`, respectively. Let the binding energies per nucleon of `._(92)^(236)U, ._(54)^(140)Xe` and `._(38)^(94)Sr` be `7.5 MeV, 8.5 Me V` and `8.5 MeV`, respectively. Considering different conservation laws, the correct options `(s)` is (are)
A. x=n, y=n, `K_"Sr"`=129 MeV, `K_"Xe"`=86 MeV
B. x=p, y=`e^-`, `K_"Sr"`=129 MeV, `K_"Xe"`=86 MeV
C. x=p, y=n, `K_"Sr"`=129 MeV, `K_"Xe"`=86 MeV
D. x=n, y=n, `K_"Sr"`=86 MeV, `K_"Xe"`=129 MeV