Question

In a close packed structure of mixed oxides , the lattice is composed of oxide ions , one eighth of tetrahedral voids are occupied by divalent cations while one half of octahedral voids are occupied by trivalent cations . What is the formula of the oxide ?
A. `A_2BO_4`
B. `AB_2O_3`
C. `A_2BO_3`
D. `AB_2O_4`

Answer 1

Correct Answer - D
Number of oxide ions(O) per unit cell=1
Number of tetrahedral voids per ion in lattice = 2
Number of divalent cation (A)=`1/8xx2=1/4`
Number of octahedral voids per ion ini lattice = 1
Number of trivalent cations (B)=`1xx1/2=1/2`
Formula = `A_(1//4)B_(1//2)O=AB_2O_4`