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In a parallelogram ABCD, if ∠A = (3x + 12)°, ∠B = (2x – 32)°, then liptl the value of x and the measures of ∠C and ∠D

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□ABCD is a parallelogram. [Given] 

∴ ∠A + ∠B = 180° [Adjacent angles of a 

parallelogram are supplementary], 

∴ (3x + 12)° + (2x-32)° = 180°

∴ 3x + 12 + 2x – 32 = 180 

∴ 5x – 20 = 180

∴ 5x= 180 + 20 

∴ 5x = 200 

∴ x =\(\frac{200}{5}\)

∴ x = 40

ii. ∠A = (3x + 12)° 

= [3(40) + 12]° 

=(120 +12)°= 132°

∠B = (2x – 32)° 

= [2(40) – 32]° 

= (80 – 32)° = 48° 

∴ ∠C = ∠A = 132° 

∠D = ∠B = 48° [Opposite angles of a parallelogram] 

∴ The value of x is 40, and the measures of ∠C and ∠D are 132° and 48° respectively.

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