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Find the approximate values of: log e^(9.01), given that log 3 = 1.0986.

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Find the approximate values of:

loge(9.01), given that log 3 = 1.0986.

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1 Answer

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Best answer

Let f(x) - logex.

Then f'(x) = 1/x

Take a = 100 and h = 1. then

The formula for a approximation is

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